PROGRAM FOR ARRAY IN C++

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19

#include <iostream.h> void main() { const int rows = 4; const int cols = 4; // declaration int ** a; // allocation a = new int*[rows]; for(int i = 0; i < rows; i++) a[i] = new int[cols]; // initialization for(int j = 0; j < rows; j++) for(int i = 0; i < rows; i++) a[i][j] = 0; }

I just give you a simple example here:

1 2 3 4 5 6

void main() { byte * str; str = (byte *) calloc(100, sizeof(byte)); // this is specific for arrays // or: str = (byte *) malloc(100); // this is only for byte arrays free(str); }

I hope it can help you!
Good luck!you can use the new instruction only to allocate object of a class type,
you defined byte as a unsigned char, this is a primitive type, it's not a class so it doesn't work.

you may use the C calloc(...) function but it's not very simple at first sight

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17

#include <iostream.h> typedef unsigned char byte; byte ** createByteMatrix(unsigned int rows, unsigned int cols) { byte ** matrix; matrix = (byte **) calloc(cols, sizeof(byte *)); for(unsigned int i = 0; i < cols; i++) matrix[i] = (byte *) calloc(rows, sizeof(byte)); return matrix; } void main() { byte ** BitmapArray; BitmapArray = createByteMatrix(5, 5); BitmapArray[0][0] = 0; }

Any way to make a multi dimensional dynamic array?

1 2 3 4 5 6

typedef unsigned char byte; byte * BitmapArray; void whatever() { BitmapArray = new byte[5][5]; }